Finding Ecell for a Reaction

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Published 2013-01-31

How to find Ecell for a chemical reaction.
Here, I don't even tell you which direction the cell goes ... we'll figure it out along the way!

Check me out: www.chemistnate.com/

All Comments (21)

@runekid2 8 years ago

exam in 40 mins thanks for saving me
@masghar14 9 years ago

To keep people from getting confused, you could also point out that if you left the Fe equation as is (instead of flipping it) you could have done 0.34-(-0.44) which would give the same number, because that's how I was taught it: Ereduction-Eoxidation
@BboySuperFreeze 10 years ago

This one video cleared everything up for me since you showed both sides of spontaneous and non spontaneous. Thanks a lot!
@yushiliang1 10 years ago

The equation E cell = E cathode - E anode works like this: 0.34 - (- 0.44) = 0.78 , which is the same as what CHEMIST Nate did. He just flipped the sign to make it the 'oxidation potential'
@tanjiro57 6 years ago

The best Chemistry teacher...You should teach chemistry to my teacher!
@NumairQureshi 10 years ago

Thanks for the awesome video. I love your teaching style.
@alexbarrelet9149 9 years ago

Really helpful, thanks for making it clear!
@MrMoonfirespam 9 years ago

This video helped so much. Keep it up!
@siminling5678 5 years ago

This video helps me a lot. Thank you!!
@658magnus 10 years ago

Hey, I like your videos but I've got one question. Given the formula E cell = E cathode - E anode, shouldn't it have been 0.34 - 0.44 = - 0.1 V ?
@ShubhraShandilya29 4 years ago

Wonderful explanation!! Thanks!
@ritrade 7 years ago

Really nice explanation
@nadirbaitsaleem7270 4 years ago

Thank you, this is a useful trick!
@Scoxn 11 years ago

Awesome drawing! Your videos are great :D
@lrissunflower 8 years ago

using copper and magnesium and both their reduction potentials, i did eCathode - eAnode : 0.34--2.37 = 2.71, spontaneous, is this correct?
@sohanroy7833 7 years ago

awesome explanation!!!
@peclesswonder 9 years ago

thanks this was really helpful!!
@gon2407 3 years ago

So simple so clear thank you
@AcousticLvr22 10 years ago

great video! really helpful
@manlinpan2705 7 years ago

Thank you so much for helping me!!!!