Finding absolute extrema on a closed interval | AP Calculus AB | Khan Academy

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Published 2014-03-21
Sal finds the absolute maximum value of f(x)=8ln(x)-x_ over the interval [1,4]. Created by Sal Khan.

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All Comments (16)
  • @nombla1111
    I feel like you're following my Calc 1 class syllabus. Good stuff!
  • @johannjames8941
    Your videos are just amazing...it helps me understand the concepts easier.
  • @murtez22
    همزين فاهمها من ايام السادس 😂هذا موضوع النقط الحرحة و النهايات المحلية 😆
  • according to the graph of this function, i guess theres no absolute minimum. but is there a relative minimum?
  • @juju141
    So basically you get the absolute max when you set f’(x) equal to 0?
  • @juju141
    How do you find the absolute minimum?
  • @legolad444
    Isn't 8ln1-1^2=positive 1 due to the fact (-1^2)?
  • I’m only nine years old I’m to young for this is this for collage cause I think it is
  • @sergey_zatsepin
    Really, Sal? You used calculator? Why no intevals like we did before? I mean you can take the derivative and then on interval place points "1","2","4" and so look where derivative is positive and where is negative, that's how you easily can define that "2" is the maximum point without any calculator.