15.2 Le Chatelier's Principle | General Chemistry

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Published 2022-01-25
Chad provides a comprehensive lesson on Le Chatelier's Principle which states that if a stress is placed on a system at equilibrium, the system will respond to counteract the stress. If you're at all struggling with this concept, then check out this lesson as Chad explains Le Chatelier's Principle from 3 different perspectives: based upon the definition, by comparing the reaction quotient (Q) to the equilibrium constant (K), and by comparing the forward rate to the reverse rate. They all reinforce each other to help the student correctly predict whether a system will shift left or shift right including how to predict temperature and pressure effects.

I've embedded this playlist as a course on my website with all the lessons organized by chapter in a collapsible menu and much of the content from the study guide included on the page. Check this lesson out at www.chadsprep.com/chads-general-chemistry-videos/w…

If you want all my study guides, quizzes, final exam reviews, and practice exams, check out my General Chemistry Master Course (free trial available) at www.chadsprep.com/genchem-youtube

00:00 Lesson Introduction
00:28 Introduction to Le Chatelier's Principle
01:10 The Reactions Quotient and Comparing Q to K
06:14 Adding a Reactant (Shift Right)
09:21 Removing a Product (Shift Right)
12:15 Adding a Solid (No Shift)
13:41 Changing the Temperature
17:52 Changing the Pressure
21:24 Adding an Inert Gas

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All Comments (21)
  • HOW IS CHAD NOT MONETIZED??? He's literally the best! I've been having a hard time understanding what happens if the pressure is changed and this is the only video that helped me. Binging his other videos!
  • @mambo5431
    i just want to let you know that youre helping out people (like me just now) with your videos to this day
  • @itsdhrubo9011
    It is hard to get such quality lectures on YouTube. Very well explained and hope you will keep up the good work...
  • @ashleem3295
    I am so thankful I found your videos! You are a great teacher, and I wish I had found you in gen chem 1! I love that you take the time to teach each aspect of the section. My professor teaches quickly and skips many small steps, so your videos help me actually learn the material.
  • @user-vl1bk9jh4h
    Sir l know you are the only teacher who can clear away my all confusions relevant to my questions😢
  • @ConnorStear
    I had to stop and applaud how beautifully simple you made everything right around the range of 3:40 to 4:40. Everything clicked so well it's like I could feel the neurons firing in my brain lol.
  • @life0fjah
    youre the best man, you explain things so well! THANK YOU!
  • @saqibkhan3364
    Chad, In the last lecture you said that only temperature can change the equilibrium constant. So it is fair to say that when we are are changing the concentration of reactants and products, we are not changing the equilibrium constant but rather the reaction quotient. So when we change the reaction quotient, this shifts the reaction in a way that allows us to get back to the equilibrium constant which remains the same value because only temperature can change the equilibrium constant? (I hope this makes sense).
  • Hi, you said shifting to the right causes the Q value to go up, I thought it causes it to go down since it Q
  • @devikanair44
    thank you so much for explaining the effects with temperature. I was struggling with that for a long time b/c I was confused how shifting T changes a rxn b/c it affects equilibrium. One quick question! how would you reconcile that delta G = -RTlnK but if you added heat in an exothermic reaction the delta G should be less negative, but according to the formula if you increase temperature the Delta G would be more negative? loving the new playlist!!
  • @user-vl1bk9jh4h
    Dear sir you asked that change in conc of either reactants or products at eq doesn't affect the value of Kc but if we increase the conc of O2 here the reaction will go in forward direction and reverse reaction remains unchanged and after a second the consumption of extra O2 again rate of forward reaction also becomes slow down and both rates again become equal . In other hand if at eq we decrease the conc of Co the reaction will go in forward direction but in this case we have no extra addition of reactants or products but our normally present reactants at eq are consuming and in this case the rate of reverse reaction slow down and after a second both the rates again become equal sir how both these reactions could have equal value of Kc😢😢😢😢
  • @saqibkhan3364
    Another Question, What if we decrease the pressure by increasing the volume? How would this effect the shift of the rxn?